Optimal. Leaf size=203 \[ \frac {i \left (a+b \tan ^{-1}(c x)\right )}{c^4 d^2 (-c x+i)}-\frac {3 \log \left (\frac {2}{1+i c x}\right ) \left (a+b \tan ^{-1}(c x)\right )}{c^4 d^2}-\frac {x^2 \left (a+b \tan ^{-1}(c x)\right )}{2 c^2 d^2}-\frac {2 i a x}{c^3 d^2}-\frac {3 i b \text {Li}_2\left (1-\frac {2}{i c x+1}\right )}{2 c^4 d^2}+\frac {b}{2 c^4 d^2 (-c x+i)}-\frac {b \tan ^{-1}(c x)}{c^4 d^2}+\frac {b x}{2 c^3 d^2}-\frac {2 i b x \tan ^{-1}(c x)}{c^3 d^2}+\frac {i b \log \left (c^2 x^2+1\right )}{c^4 d^2} \]
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Rubi [A] time = 0.22, antiderivative size = 203, normalized size of antiderivative = 1.00, number of steps used = 16, number of rules used = 12, integrand size = 23, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.522, Rules used = {4876, 4846, 260, 4852, 321, 203, 4862, 627, 44, 4854, 2402, 2315} \[ -\frac {3 i b \text {PolyLog}\left (2,1-\frac {2}{1+i c x}\right )}{2 c^4 d^2}-\frac {x^2 \left (a+b \tan ^{-1}(c x)\right )}{2 c^2 d^2}+\frac {i \left (a+b \tan ^{-1}(c x)\right )}{c^4 d^2 (-c x+i)}-\frac {3 \log \left (\frac {2}{1+i c x}\right ) \left (a+b \tan ^{-1}(c x)\right )}{c^4 d^2}-\frac {2 i a x}{c^3 d^2}+\frac {i b \log \left (c^2 x^2+1\right )}{c^4 d^2}+\frac {b x}{2 c^3 d^2}+\frac {b}{2 c^4 d^2 (-c x+i)}-\frac {2 i b x \tan ^{-1}(c x)}{c^3 d^2}-\frac {b \tan ^{-1}(c x)}{c^4 d^2} \]
Antiderivative was successfully verified.
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Rule 44
Rule 203
Rule 260
Rule 321
Rule 627
Rule 2315
Rule 2402
Rule 4846
Rule 4852
Rule 4854
Rule 4862
Rule 4876
Rubi steps
\begin {align*} \int \frac {x^3 \left (a+b \tan ^{-1}(c x)\right )}{(d+i c d x)^2} \, dx &=\int \left (-\frac {2 i \left (a+b \tan ^{-1}(c x)\right )}{c^3 d^2}-\frac {x \left (a+b \tan ^{-1}(c x)\right )}{c^2 d^2}+\frac {i \left (a+b \tan ^{-1}(c x)\right )}{c^3 d^2 (-i+c x)^2}+\frac {3 \left (a+b \tan ^{-1}(c x)\right )}{c^3 d^2 (-i+c x)}\right ) \, dx\\ &=\frac {i \int \frac {a+b \tan ^{-1}(c x)}{(-i+c x)^2} \, dx}{c^3 d^2}-\frac {(2 i) \int \left (a+b \tan ^{-1}(c x)\right ) \, dx}{c^3 d^2}+\frac {3 \int \frac {a+b \tan ^{-1}(c x)}{-i+c x} \, dx}{c^3 d^2}-\frac {\int x \left (a+b \tan ^{-1}(c x)\right ) \, dx}{c^2 d^2}\\ &=-\frac {2 i a x}{c^3 d^2}-\frac {x^2 \left (a+b \tan ^{-1}(c x)\right )}{2 c^2 d^2}+\frac {i \left (a+b \tan ^{-1}(c x)\right )}{c^4 d^2 (i-c x)}-\frac {3 \left (a+b \tan ^{-1}(c x)\right ) \log \left (\frac {2}{1+i c x}\right )}{c^4 d^2}+\frac {(i b) \int \frac {1}{(-i+c x) \left (1+c^2 x^2\right )} \, dx}{c^3 d^2}-\frac {(2 i b) \int \tan ^{-1}(c x) \, dx}{c^3 d^2}+\frac {(3 b) \int \frac {\log \left (\frac {2}{1+i c x}\right )}{1+c^2 x^2} \, dx}{c^3 d^2}+\frac {b \int \frac {x^2}{1+c^2 x^2} \, dx}{2 c d^2}\\ &=-\frac {2 i a x}{c^3 d^2}+\frac {b x}{2 c^3 d^2}-\frac {2 i b x \tan ^{-1}(c x)}{c^3 d^2}-\frac {x^2 \left (a+b \tan ^{-1}(c x)\right )}{2 c^2 d^2}+\frac {i \left (a+b \tan ^{-1}(c x)\right )}{c^4 d^2 (i-c x)}-\frac {3 \left (a+b \tan ^{-1}(c x)\right ) \log \left (\frac {2}{1+i c x}\right )}{c^4 d^2}-\frac {(3 i b) \operatorname {Subst}\left (\int \frac {\log (2 x)}{1-2 x} \, dx,x,\frac {1}{1+i c x}\right )}{c^4 d^2}+\frac {(i b) \int \frac {1}{(-i+c x)^2 (i+c x)} \, dx}{c^3 d^2}-\frac {b \int \frac {1}{1+c^2 x^2} \, dx}{2 c^3 d^2}+\frac {(2 i b) \int \frac {x}{1+c^2 x^2} \, dx}{c^2 d^2}\\ &=-\frac {2 i a x}{c^3 d^2}+\frac {b x}{2 c^3 d^2}-\frac {b \tan ^{-1}(c x)}{2 c^4 d^2}-\frac {2 i b x \tan ^{-1}(c x)}{c^3 d^2}-\frac {x^2 \left (a+b \tan ^{-1}(c x)\right )}{2 c^2 d^2}+\frac {i \left (a+b \tan ^{-1}(c x)\right )}{c^4 d^2 (i-c x)}-\frac {3 \left (a+b \tan ^{-1}(c x)\right ) \log \left (\frac {2}{1+i c x}\right )}{c^4 d^2}+\frac {i b \log \left (1+c^2 x^2\right )}{c^4 d^2}-\frac {3 i b \text {Li}_2\left (1-\frac {2}{1+i c x}\right )}{2 c^4 d^2}+\frac {(i b) \int \left (-\frac {i}{2 (-i+c x)^2}+\frac {i}{2 \left (1+c^2 x^2\right )}\right ) \, dx}{c^3 d^2}\\ &=-\frac {2 i a x}{c^3 d^2}+\frac {b x}{2 c^3 d^2}+\frac {b}{2 c^4 d^2 (i-c x)}-\frac {b \tan ^{-1}(c x)}{2 c^4 d^2}-\frac {2 i b x \tan ^{-1}(c x)}{c^3 d^2}-\frac {x^2 \left (a+b \tan ^{-1}(c x)\right )}{2 c^2 d^2}+\frac {i \left (a+b \tan ^{-1}(c x)\right )}{c^4 d^2 (i-c x)}-\frac {3 \left (a+b \tan ^{-1}(c x)\right ) \log \left (\frac {2}{1+i c x}\right )}{c^4 d^2}+\frac {i b \log \left (1+c^2 x^2\right )}{c^4 d^2}-\frac {3 i b \text {Li}_2\left (1-\frac {2}{1+i c x}\right )}{2 c^4 d^2}-\frac {b \int \frac {1}{1+c^2 x^2} \, dx}{2 c^3 d^2}\\ &=-\frac {2 i a x}{c^3 d^2}+\frac {b x}{2 c^3 d^2}+\frac {b}{2 c^4 d^2 (i-c x)}-\frac {b \tan ^{-1}(c x)}{c^4 d^2}-\frac {2 i b x \tan ^{-1}(c x)}{c^3 d^2}-\frac {x^2 \left (a+b \tan ^{-1}(c x)\right )}{2 c^2 d^2}+\frac {i \left (a+b \tan ^{-1}(c x)\right )}{c^4 d^2 (i-c x)}-\frac {3 \left (a+b \tan ^{-1}(c x)\right ) \log \left (\frac {2}{1+i c x}\right )}{c^4 d^2}+\frac {i b \log \left (1+c^2 x^2\right )}{c^4 d^2}-\frac {3 i b \text {Li}_2\left (1-\frac {2}{1+i c x}\right )}{2 c^4 d^2}\\ \end {align*}
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Mathematica [A] time = 1.04, size = 186, normalized size = 0.92 \[ -\frac {2 a c^2 x^2-6 a \log \left (c^2 x^2+1\right )+8 i a c x+\frac {4 i a}{c x-i}-12 i a \tan ^{-1}(c x)+b \left (-4 i \log \left (c^2 x^2+1\right )+2 \tan ^{-1}(c x) \left (c^2 x^2+4 i c x+6 \log \left (1+e^{2 i \tan ^{-1}(c x)}\right )+i \sin \left (2 \tan ^{-1}(c x)\right )-\cos \left (2 \tan ^{-1}(c x)\right )+1\right )-6 i \text {Li}_2\left (-e^{2 i \tan ^{-1}(c x)}\right )-2 c x-12 i \tan ^{-1}(c x)^2+\sin \left (2 \tan ^{-1}(c x)\right )+i \cos \left (2 \tan ^{-1}(c x)\right )\right )}{4 c^4 d^2} \]
Warning: Unable to verify antiderivative.
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fricas [F] time = 0.43, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {-i \, b x^{3} \log \left (-\frac {c x + i}{c x - i}\right ) - 2 \, a x^{3}}{2 \, {\left (c^{2} d^{2} x^{2} - 2 i \, c d^{2} x - d^{2}\right )}}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \mathit {sage}_{0} x \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.07, size = 367, normalized size = 1.81 \[ -\frac {2 i a x}{c^{3} d^{2}}-\frac {a \,x^{2}}{2 c^{2} d^{2}}-\frac {3 i b \dilog \left (-\frac {i \left (c x +i\right )}{2}\right )}{2 c^{4} d^{2}}+\frac {3 a \ln \left (c^{2} x^{2}+1\right )}{2 c^{4} d^{2}}+\frac {3 i a \arctan \left (c x \right )}{c^{4} d^{2}}-\frac {i b}{2 c^{4} d^{2}}-\frac {b \arctan \left (c x \right ) x^{2}}{2 c^{2} d^{2}}-\frac {2 i b x \arctan \left (c x \right )}{c^{3} d^{2}}+\frac {3 b \arctan \left (c x \right ) \ln \left (c x -i\right )}{c^{4} d^{2}}+\frac {3 i b \ln \left (c x -i\right )^{2}}{4 c^{4} d^{2}}-\frac {i b \arctan \left (c x \right )}{c^{4} d^{2} \left (c x -i\right )}+\frac {i b \ln \left (c^{4} x^{4}+10 c^{2} x^{2}+9\right )}{8 c^{4} d^{2}}+\frac {b x}{2 c^{3} d^{2}}+\frac {3 i b \ln \left (c^{2} x^{2}+1\right )}{4 c^{4} d^{2}}-\frac {i a}{c^{4} d^{2} \left (c x -i\right )}-\frac {b \arctan \left (\frac {c x}{2}\right )}{4 c^{4} d^{2}}+\frac {b \arctan \left (\frac {1}{6} c^{3} x^{3}+\frac {7}{6} c x \right )}{4 c^{4} d^{2}}+\frac {b \arctan \left (\frac {c x}{2}-\frac {i}{2}\right )}{2 c^{4} d^{2}}-\frac {b}{2 c^{4} d^{2} \left (c x -i\right )}-\frac {3 i b \ln \left (c x -i\right ) \ln \left (-\frac {i \left (c x +i\right )}{2}\right )}{2 c^{4} d^{2}}-\frac {3 b \arctan \left (c x \right )}{2 d^{2} c^{4}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \text {result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.00 \[ \int \frac {x^3\,\left (a+b\,\mathrm {atan}\left (c\,x\right )\right )}{{\left (d+c\,d\,x\,1{}\mathrm {i}\right )}^2} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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